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Question

If u=ab,v=a+b and a=b=2, then u×v=

A
216(a.b)2
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B
16(a.b)2
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C
24(a.b)2
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D
4(a.b)2
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Solution

The correct option is A 216(a.b)2
u×v=(ab)×(a+b)=2a×b|u×v|=2|a×b|=2a2b2sin2θ=2a2b2a2b2cos2θ=216(a.b)2[|a|=|b|=2]

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