If →x,→y are two non-zero and non-collinear vectors satisfying [(a−2)α2+(b−3)α+c]→x+[(a−2)β2+(b−3)β+c]→y+[(a−2)γ2+(b−3)γ+c](→x×→y)=→0, where α,β,γ are three distinct real numbers, then which of the following statement(s) is/are correct ?
A
a(b+c−a)=2
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B
b(c+a−b)=3
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C
c(a+b−c)=0
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D
a2+b2−c2=13
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Solution
The correct option is Da2+b2−c2=13 Given : [(a−2)α2+(b−3)α+c]→x+[(a−2)β+(b−3)β+c]→y+[(a−2)γ2+(b−3)γ+c](→x×→y)=→0,
Since →x,→y are non-collinear vectors, ⇒→x,→y and →x×→y are non-coplanar vectors.
So, cofficient of each vectors will be zero. (a−2)α2+(b−3)α+c=0(a−2)β2+(b−3)β+c=0(a−2)γ2+(b−3)γ+c=0
So, α,β,γ are three distnict real roots of the equation (a−2)x2+(b−3)x+c=0
A quadratic equation with more than 2 roots will be an identity. ⇒a=2,b=3,c=0