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Raoult's Law

If P0 and ...

Question

If $P^{0}$ and $P_{S}$ are the V.P. of solvent and its solution respectively and $N_{1}$ and $N_{2}$ are the mole fraction of solvent and solute respectively then:

P_{S} = P^{0} N_{2}

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P^{0} - P_{S} = P^{0} N_{2}

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P_{S} = P^{0} N_{1}

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(P^{0} - P_{S}) / P_{S} = N_{1} / (N_{1} + N_{2})

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Solution

The correct options are
A $P_{S} = P^{0} N_{1}$
B $P^{0} - P_{S} = P^{0} N_{2}$
If $P^{0}$ and $P_{S}$ are the V.P. of solvent and its solution respectively and $N_{1}$ and $N_{2}$ are the mole fraction of solvent and solute respectively then,
Relative lowering vapour pressure,
$P^{0} - P_{S} = P^{0} N_{2}$
As per Raoult's Law,
and $P_{S} = P^{0} N_{1} = P^{0} (1 - N_{2})$

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