Question

If $P_1$ is the perimeter of shape 1 and $P_2$ is the perimeter of shape 2, then:

• A. $P_1<P_2$
• B. $P_1=P_2$
• C. $P_1>P_2$
• D. None of the above

Answer 1

The correct option is B $P_1=P_2$


Shape 1 is a rectangle with a length of 15 m and width of 9 m.
The perimeter of a rectangle is given by the formula, $2(l+w)$, where $l$ is the length and $w$ is the width of the rectangle.

$P_1=$ Perimeter of shape $1=2(15+9)$
$=2\times 24=48m$

Shape 2 is a square with a side of 12 m.
The perimeter of a square is given by the formula, $4\times \text{side}$.

$P_2=$ Perimeter of shape $2=4\times 12$
$=48m$
$\therefore P_1=P_2$
Hence, option (b.) is the correct choice.