If $p = 1, q = 2$ and $r = - 3$ find the value of :
$p^{3} + q^{3} + - r^{3}$

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Solution

$= p^{3} + q^{3} + - r^{3} = {(1)}^{3} + {(2)}^{3} - {(- 3)}^{3} = 1 + 8 - (- 27) = 1 + 8 + 27 = 36$

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Similar questions

If q is the mean proportional between p and r prove that :

$\frac{p^{3} + q^{3} + r^{3}}{p^{2} q^{2} r^{2}} = \frac{1}{p^{3}} + \frac{1}{q^{3}} + \frac{1}{r^{3}}$

p = - 2, q = 1

r = 3

p^{2} + q^{2} - r^{2}

p - q - r

p^{3} + q^{3} + r^{3} + 3 p q r

p^{3} {(q - r)}^{3} + q^{3} {(r - p)}^{3} + r^{3} {(p - q)}^{3}

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