Question

If $P_1$ represents momentum of a matter particle and $P_2$ is momentum of a photon, the ratio of $P_1:P_2$ is, ($\lambda$ is the wavelength of the photon)
Here, $v$ is the velocity of the particle.

• A. $\frac{\left(m\lambda v\right)}{h}$
• B. $\frac{\left(mv{\lambda }^2\right)}{h}$
• C. $\frac{\left(2m\lambda v\right)}{h}$
• D. $1:1$

Answer 1

The correct option is A $\frac{\left(m\lambda v\right)}{h}$

Given:
$P_1=$ momentum of matter particle
$\Rightarrow P_1=mv$
and, $P_2=$ momentum of photons
$\Rightarrow P_2=\frac{h}{\lambda }$

$\therefore \frac{P_1}{P_2}=\frac{mv}{\frac{h}{\lambda }}=\frac{m\lambda v}{h}$

Hence, $\left(A\right)$ is the correct answer.