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Question

If (p+1)th term of an A.P. is twice the (q+1)th term, Prove that the (3p+1)th term=m(p+1)th term.Find m

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Solution

(p+1) term of A.P.=2[(9+14)term]a+pd=2a+22d(3p+1)term=m[(p+q+1)term]a+3pd=m[a+(p+2d)]2a+22d+2pd=m[a+(p+q)d]2(a+(p+q)d)=m[a+(p+q)d]m=2

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