If p=1×1!+2×2!+3×3!+...+10×10!, then the remainder when p+2 is divided by 11! is
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Solution
p=1×1!+2×2!+3×3!+...+10×10! ⇒p=(2−1)1!+(3−1)×2!+(4−1)×3!+...+(11−1)×10! ⇒p=2!−1!+3!−2!+4!−3!+...+11!−10! ⇒p=11!−1 ⇒p+2=11!+1 When p+2 is divided by 11!, we get remainder as 1