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Question

If p=1×1!+2×2!+3×3!+...+10×10!, then the remainder when p+2 is divided by 11! is

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Solution

p=1×1!+2×2!+3×3!+...+10×10!
p=(21)1!+(31)×2!+(41)×3!+...+(111)×10!
p=2!1!+3!2!+4!3!+...+11!10!
p=11!1
p+2=11!+1
When p+2 is divided by 11!, we get remainder as 1

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