CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If p=1×1!+2×2!+3×3!+...+10×10!, then the remainder when p+2 is divided by 11! is

Open in App
Solution

p=1×1!+2×2!+3×3!+...+10×10!
p=(21)1!+(31)×2!+(41)×3!+...+(111)×10!
p=2!1!+3!2!+4!3!+...+11!10!
p=11!1
p+2=11!+1
When p+2 is divided by 11!, we get remainder as 1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Permutations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon