If P = (15,√2) be a point and L = x−1√2=y−21=z−31=r be a line if PQ is the distance of plane √2x+y−z−1=0 from P measured along a line inclined at an angle of 60o with line L and is minimum, then PQ is equal to
A
1 unit
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B
2√3 units
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C
2 units
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D
5 units.
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Solution
The correct option is A 1 unit
P = (15,√2) be a point
and L = x−1√2=y−21=z−31=r be a line
PQ is the distance of plane √2x+y−z−1=0 from P
measured along a line inclined at an angle of 60o with line L and is minimum,