CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If P1P2 and P3P4 are two focal chord of the parabola y2=4ax then the chord P1P3 and P2P4 are intersecting on

A
directrix
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
vertex
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
on parabola
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
not intersect
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B directrix
If P1P2 are two focal chord of parabola y2=4ax then cord P1P3 and P2P4 are intersect at :
P1(at21,2at1),Q2(at21,2at1)P1(at22,2at2),Q2(at22,2at2)
Equation of P1Q2
y2at1=2at22at1at22at21(xat21)y2at1=2t11t2(xat21)........(1)
Equation of P2Q1
y2at2=2at12at2at21at22(xat22)y2at2=2t21t1(xat22)........(2)
Solve (1) and (2)
2a(t2t1)=2t1t21[t2(xat21)t1(xat22)]a(t2t1)(t1t21)=(t2t1)[x+at2t1]at2t1a=x+at2t1x=a
Therefore intersection of point of P1Q2 and P2Q1 lies on directrix.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hyperbola and Terminologies
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon