If $p = (2 - a)$ , then the value of $a^{3} + 6 a p + p^{3} - 8$ , is ___.

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Solution

The correct option is A 0
$a^{3} + 6 a p + (p^{3} - 8) = a^{3} + 6 a p + (p - 2) (p^{2} + 2 p + 4)$
$= a^{3} + (6 a (2 - a)) + (- a) (4 + a^{2} - 4 a + 4 - 2 a + 4)$
$= a^{3} + 12 a - 6 a^{2} - a (a^{2} - 6 a + 12)$
$= 0$

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Similar questions

Find the value of a³+6ap+p³-8 when p=2-a

p = 2 - a

a^{3} + 6 a p + p^{3} - 8 = 0

If the value of $(\frac{a^{3} - b^{3}}{a^{3} + b^{3}})$ when a = 7 and b = 2 is $\frac{335}{p}$ , then p is 321.

If the value of $(\frac{a^{3} - b^{3}}{a^{3} + b^{3}})$ , when $a = 7$ and $b = 2$ is $\frac{335}{p}$ , then $p$ is $321$ .

C = {p | p \in I, p^{3} = - 8}

C

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