(1) p2 + q2
Substituting the values of p and q in the given algebraic expression, we get:
(3)2 + (5)2
= 9 + 25 (Solving the simple brackets first)
= 34
(2) p2 − 2pq + q2
Substituting the values of p and q in the given algebraic expression, we get:
(3)2 − 2 × 3 × 5 + (5)2
= 9 − 2 × 3 × 5 + 25 (Solving the simple brackets first)
= 9 − 30 + 25 (Performing multiplication first)
= 34 − 30 (Performing addition first)
= 4
(3) qp + 3q
Substituting the values of p and q in the given algebraic expression, we get:
5 × 3 + 3 × 5
= 15 + 15 (Performing multiplication first)
= 30
(4) p2 + 2p + q
Substituting the values of p and q in the given algebraic expression, we get:
(3)2 + 2 × 3 + 5
= 9 + 2 × 3 + 5 (Solving the simple brackets first)
= 9 + 6 + 5 (Performing multiplication first)
= 20