If $P = 3 x - 4 y - 8 z, Q = - 10 y + 7 x + 11 z$ and $R = 19 z - 6 y + 4 x$ , then $P - Q + R$ is equal to

13 x - 20 y + 16 z

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x + y + z

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 x - b y + 3 z

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 0
$P - Q + R$ $= 3 x - 4 y - 8 z - (7 x - 10 y + 11 z) + (4 x - 6 y + 19 z)$
$P - Q + R$ $= 3 x - 4 y - 8 z - 7 x + 10 y - 11 z + 4 x - 6 y + 19 z = (3 - 7 + 4) x + (- 4 + 10 - 6) y + (- 8 - 11 + 19) z = 0$

Suggest Corrections

Similar questions

p, q

r

p + q + r

\neq

x + 2 y - 3 z = p

2 x + 6 y - 11 z = q

x - 2 y + 7 z = r

If p, q, r are in A.P. and x, y, z are in G.P. then $x^{q - r} . y^{r - p} . z^{p - q}$ is equal to

P = {3 x}^{2} + 7 x + 8, Q = {2 x}^{2} + x - 9

R = - {5 x}^{2} - 8 x + 1

P + Q + R = 0

x^{q - r} . y^{r - p} . z^{p - q}

Join BYJU'S Learning Program