You visited us 1 times! Enjoying our articles? Unlock Full Access!

Complementary Angles

If ∠ P =3 x a...

Question

If ∠P = 3x and ∠Q = 6x such that ∠P and ∠Q are complementary then the value of x is:

10^o

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

30^o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20^o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40^o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
10^o

Since, angles P and Q are complementary, we have

∠P + ∠Q = 90^o

i.e. 3x + 6x = 90^o

Or, 9x = 90^o

Or, x = 10^o

Suggest Corrections

Similar questions

a

b

x^{2} - 3 x + p = 0

c, d

x^{2} - 3 x + p = 0,

a, b, c, d

(q + p) : (q - p) = 17 : 15

x^{2} - 3 x + p = 0

x^{2} - 12 x + q

a, b, c a n d d

(q + p) : (q - p) = 17 : 15

Given that a, b, c, d, p and q are natural numbers such that a < b and d < c. It is also given that the following result holds true:

$\frac{a}{b} \times \frac{d}{c} = \frac{q}{p}$

Choose the correct option(s):

If (x-p) and (x-q) are the factors of the expression $a x^{2} + b x + c$ , then the values of $a$ and $b$ are:

Given that a, b, c, d, p and q are natural numbers such that a < b and d < c. It is also given that the following result holds true:

$\frac{a}{b} \times \frac{d}{c} = \frac{q}{p}$

Choose the correct option(s):

Join BYJU'S Learning Program