If P = {4, 5, 6, 7, 8, 9}, Q = {2, 3, 4}, R = {4, 5, 8} then .

P \subseteq Q

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R \subseteq P

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Q \subseteq R

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Solution

The correct option is B $R \subseteq P$

All the elements of R are elements of P.

$\Rightarrow R \subseteq P$

Also, both Q and R have the same number of elements.

$\Rightarrow$ They are equivalent sets.

$P ⊈ Q$ as $6 \in P,$ but $6 \notin Q .$

$Q ⊈ R$ as $2 \in Q,$ but $2 \notin R .$

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If P = {4, 5, 6, 7, 8, 9}, Q = {2, 3, 4}, R = {4, 5, 8} then .

The correct option is B R⊆P All the elements of R are elements of P. ⇒R⊆P Also, both Q and R have the same number of elements. ⇒ They are equivalent sets. P⊈Q as 6∈P, but 6∉Q. Q⊈R as 2∈Q, but 2∉R.

The correct option is B $R \subseteq P$

All the elements of R are elements of P.

$\Rightarrow R \subseteq P$

Also, both Q and R have the same number of elements.

$\Rightarrow$ They are equivalent sets.

$P ⊈ Q$ as $6 \in P,$ but $6 \notin Q .$

$Q ⊈ R$ as $2 \in Q,$ but $2 \notin R .$