325
Question
If P = 7a - [6b - {9a - (5c + 12b) + 5c - 5 (3a - 5b)}]
and Q = 6a - [15b - {8a - (4c + 11b) + 4c}].
then (16P + 7Q) is equal to:
If P = 7a - [6b - {9a - (5c + 12b) + 5c - 5 (3a - 5b)}]
and Q = 6a - [15b - {8a - (4c + 11b) + 4c}].
then (16P + 7Q) is equal to:
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Solution
The correct option is D 114a-294b
Given
P=7a−[6b−{9a−(5c+12b)+5c−5(3a−5b)}]
=7a−[6b−{9a−5c−12b+5c−15a+25b}]
=7a−[6b−(−6a+13b)]
=7a−[6b+6a−13b]
=7a−[6a−7b]
=7a−6a+7b
=a−7b
Q=6a−[15b−{8a−(4c+11b)+4c}]
=6a−[15b−{8a−4c−11b+4c}]
=6a−[15b−{8a−11b}]
=6a−[15b−8a+11b]
=6a−[26b−8a]
=14a−26b
16P+7Q
=16(a−7b)+7(14a−26b)
=16a−112b+98a−182b
=114a−294b
Given
P=7a−[6b−{9a−(5c+12b)+5c−5(3a−5b)}]
=7a−[6b−{9a−5c−12b+5c−15a+25b}]
=7a−[6b−(−6a+13b)]
=7a−[6b+6a−13b]
=7a−[6a−7b]
=7a−6a+7b
=a−7b
Q=6a−[15b−{8a−(4c+11b)+4c}]
=6a−[15b−{8a−4c−11b+4c}]
=6a−[15b−{8a−11b}]
=6a−[15b−8a+11b]
=6a−[26b−8a]
=14a−26b
16P+7Q
=16(a−7b)+7(14a−26b)
=16a−112b+98a−182b
=114a−294b
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