If P-7 x2-5 x y-9 y2- Q-4 y2-3 x2-6 x y and R-4 x2-x y-5 y2- show that P-Q-R-0-

We have P + Q + R = (7x2 + 5xy 9y2) + (4y2 3x2 6xy) + ( 4x2 + xy + 5y2) nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; ...

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Addition of Algebraic Expressions

If P=7 x2+5 x...

Question

If P = 7x² + 5xy − 9y², Q = 4y² − 3x² − 6xy and R = −4x² + xy + 5y², show that P + Q + R = 0.

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Solution

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P = 7 x^{2} + 5 x y - 9 y^{2}, Q = 4 y^{2} - 3 x^{2}

R = 4 x^{2} + x y + 5 y^{2}

P + Q + R = 8 x^{2} + 6 x y

3 x^{2} + 5 x y - 4 y^{2} + x^{2} - 8 x y - 5 y^{2}

4 x^{2} - 3 x y - 9 y^{2}

3 x^{2} - 4 y^{2} + 5 x y + 20

- x^{2} - y^{2} + 6 x y + 20

P = {3 x}^{2} + 7 x + 8, Q = {2 x}^{2} + x - 9

R = - {5 x}^{2} - 8 x + 1

P + Q + R = 0

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