If $p = 99$ then find the value of $p (p^{2} + 3 p + 3)$ .

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Solution

Now,
$p (p^{2} + 3 p + 3)$
$= p^{3} + 3 p^{2} + 3 p + 1 - 1$
$= (p + 1)^{3} - 1$
$= (100)^{3} - 1$ [ Since $p = 99$ ]
$= 99, 9999$

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