If PA-0-4- PA - B-0-7 and the events are mutually exclusive- then PB-

Given, nbsp; nbsp;P(A) = 0.4 P(A #8746;B) = 0.7 P(A⋂B) = 0 nbsp; ( there4; A and B are mutually exclusive) then nbsp;P(A #8746;B) = P(A) + P(B) ...

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Conditional Probability

If PA=0.4, PA...

Question

If P(A) = 0.4, P(A $\cup$ B) = 0.7 and the events are mutually exclusive, then P(B) =____________.

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Solution

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P (A / B) = P (B / A)

P (A) = P (B)

(A \cap B) \neq ϕ

P (A / B) = \frac{P (A \cap B)}{P (B)}

P (B / A) = \frac{P (A \cap B)}{P (A)}

If A and B are mutually exclusive events such that P(A = 0.35 and P(B=0.45, find

(i) $P (A \cup B)$

(ii) $P (A \cap B)$

(iii) $P (A \cap ¯ ¯¯ ¯ B)$

(iv) $P (¯ ¯¯ ¯ A \cap ¯ ¯¯ ¯ B)$

If A and B are mutually exclusive events then
(a) PA≤PB
(b) PA≥PB
(c) PA<PB
(d) None of these

P (A) = \frac{1}{4}

P (B) = \frac{1}{6}

P (C) = \frac{2}{3}

P (A \cup B \cup C) = P (A) + P (B) + P (C)

P (A \cap B)

A

B

P (A \cap B)

B

A

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