Question

If $P\left(A\right)=0.8$ and $P\left(B|A\right)=0.4$, Find $P(A\cap B)$

Answer 1

We, know that,

$P\left(B|A\right)=\frac{P(A\cap B)}{P\left(A\right)}$

$P(A\cap B)=P\left(A\right).P\left(B|A\right)$

$P(A\cap B)=0.8\times 0.4$

$P(A\cap B)=0.32$