If P (A)=0.8,P(B)=0.5 and P(BA)=0.4, find
P(A∩B)
P(AB)
P(A∪B)
Given, P(A)=0.8,P(B)=0.5,P(BA)=0.4⇒P(A∩B)P(A)=0.4[P(BA)=P(A∩B)P(A)]⇒P(A∩B)0.8=0.4⇒P(A∩B)=0.8×0.4=0.32
P(AB)=P(A∩B)P(B)=0.320.5=3250=0.64
From the relation P(A∪B)=P(A)+P(B)−P(A∩B)=0.8+0.5−0.32=1.3−0.32=0.98