If P = {a, b, c} and Q = {b, c, d} ; find number of elements in (P∩Q)×P
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Solution
Given,
P = {a, b, c} and Q = {b, c, d}
Intersection of two sets has the elements which are common in both the sets. So, P∩Q={b,c} Cartesian product of two sets is found by forming ordered pairs. So, (P∩Q)×P={(b,a),(b,b),(b,c),(c,a),(c,b),(c,c)}.