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Question

If P = {a, b, c} and Q = {b, c, d} ; find number of elements in (PQ)×P

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Solution

Given,
P = {a, b, c} and Q = {b, c, d}

Intersection of two sets has the elements which are common in both the sets.
So, PQ={b,c}
Cartesian product of two sets is found by forming ordered pairs.
So, (PQ)×P={(b,a),(b,b),(b,c),(c,a),(c,b),(c,c)}.

n((PQ)×P)=6

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