If PA- B-PA- B then the relation between PA and PB is-

The correct option is A P(A) = P(B) A∪ B=nA+nB nA∩ B =nA∩ B Thus nbsp; nA+nB=2nA∩ B This is true if A=B .Hence nbsp; P(A∪ B)=P( ...

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Intersection of Sets

If PA∪ B=PA...

Question

If $P (A \cup B) = P (A \cap B)$ then the relation between $P (A)$ and $P (B)$ is..........

P (A) = P (B)

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P (A) < P (B)

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P (A) > P (B)

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None of these

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P (A \cup B) = P (A \cap B) \Leftrightarrow

P (A)

P (B)

P (A) = P (B)

P (A \cup B) = P (A \cap B),

If A and B are mutually exclusive events then
(a) PA≤PB
(b) PA≥PB
(c) PA<PB
(d) None of these

(i) P (A) = \frac{1}{3}, P (B) = \frac{1}{4} and P (A \cup B) = \frac{5}{12}, then find P (A | B) and P (B | A) . (ii) P (A) = \frac{6}{11}, P (B) = \frac{5}{11} and P (A \cup B) = \frac{7}{11}, then find P (A \cap B), P (A | B) and P (B | A) . (iii) P (A) = \frac{7}{13}, P (B) = \frac{9}{13} and P (A \cap B) = \frac{4}{13}, then find P (A | B) . (iv) P (A) = \frac{1}{2}, P (B) = \frac{1}{3} and P (A \cap B) = \frac{1}{4}, then find P (A | B), P (B | A), P (A | B) and P (A | B) .

P (A \cup B) = P (A \cap B)

P (A)

P (B)

P (A) = P (B)

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