If PA - 23- PB - 49 and PA - B - 1445 then PA- - B- - 1445 is greater than or equal to

The correct option is B 15 P(A)=2/3 P(B)=4/9 P(A #8745;B)=14/45P(AUB)=P(A)+P(B) P(A #8745;B)=2/3+4/9 14/45=36/45=4/5P(A' #8745;B')=1 P(AUB)=1 4/5=1/ ...

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Byju's Answer

Standard XII

Mathematics

Difference of Two Sets

If PA = 23,...

Question

If $P (A) = \frac{2}{3}, P (B) = \frac{4}{9}$ and $P (A \cap B) = \frac{14}{45}$ then $P (A^{'} \cap B^{'}) = \frac{14}{45}$ is greater than or equal to

\frac{37}{45}

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\frac{1}{5}

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\frac{4}{5}

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\frac{41}{45}

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Solution

The correct option is B $\frac{1}{5}$
P(A)=2/3 P(B)=4/9 P(A∩B)=14/45
P(AUB)=P(A)+P(B)-P(A∩B)=2/3+4/9-14/45=36/45=4/5
P(A'∩B')=1-P(AUB)=1-4/5=1/5

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If P(A)=23,P(B)=49 and P(A∩B)=1445 then P(A′∩B′)=1445 is greater than or equal to

The correct option is B 15P(A)=2/3 P(B)=4/9 P(A∩B)=14/45P(AUB)=P(A)+P(B)-P(A∩B)=2/3+4/9-14/45=36/45=4/5P(A'∩B')=1-P(AUB)=1-4/5=1/5

If $P (A) = \frac{2}{3}, P (B) = \frac{4}{9}$ and $P (A \cap B) = \frac{14}{45}$ then $P (A^{'} \cap B^{'}) = \frac{14}{45}$ is greater than or equal to

The correct option is B $\frac{1}{5}$
P(A)=2/3 P(B)=4/9 P(A∩B)=14/45
P(AUB)=P(A)+P(B)-P(A∩B)=2/3+4/9-14/45=36/45=4/5
P(A'∩B')=1-P(AUB)=1-4/5=1/5