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Question

If p and q are chosen randomly from the set 1,2,3,4,5,6,7,8,9,10 with replacement, determine the probability that the roots of the equation x2+px+q are real

A
3150
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B
29100
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C
38100
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D
34100
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Solution

The correct option is A 3150
Need to be solved case by case
for real roots
p24q0
p24q
pq
Total possible combinations
1-0
211
31,22
41,2,3,44
51,2,3,4,5,66
61,2,3,4,5,6,7,8,99
71,2,3,4,5,6,7,8,9,1010
81,2,3,4,5,6,7,8,9,1010
91,2,3,4,5,6,7,8,9,1010
101,2,3,4,5,6,7,8,9,1010
Total62

No. of ways of choosing p and q=10.10= 100
So P= 62100

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