Question

Question 52

If p and q are in inverse propotion, i.e. pq = k (constant), then (p + 2) and (q - 2) are also in inverse proportion.

Answer 1

False
If p and q are in inverse proportion, then
xy = k (constant)
e.g. Let p = 3 and q = 4
Then, pq = $3\times 4=12$
Now, p + 2 = 3 + 2 = 5 and q - 2 = 4 - 2 = 2
$\therefore (p+2)(q-2)=5\times 2=10$
Hence, (p + 2) and (q - 2) cannot be in inverse proportion.