If p and q are positive and p2 q2-18-3 p q- then p2-A- 18 - q 2B- 18 - q2-3 qC- 18-3 q - q3D- 9 - q 2E- 36 - q 2

The correct option is D 9/q2Subsitute q=1, the equation reduces to p2 +18 – 3p = 0. Solving this, we get p= 6 amp; p=3. Hence, p2= 9 (As p is positive) Subs ...

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Standard X

Mathematics

Polynomial

If p and q ar...

Question

If p and q are positive and p²q² = 18 – 3pq, then p² =

(18-3q) / q³

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18/q²

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18/q²+3q

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9/q²

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36/q²

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Solution

The correct option is D 9/q²
Subsitute q=1, the equation reduces to p² +18 – 3p = 0. Solving this, we get p=-6 & p=3. Hence, p²= 9 (As p is positive)

Substitute the value of q=1 in answer options to see where qou get p²= 9. Answer is option (d)

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If p and q are positive and p2q2 = 18 – 3pq, then p2 =

The correct option is D 9/q2Subsitute q=1, the equation reduces to p2 +18 – 3p = 0. Solving this, we get p=-6 & p=3. Hence, p2= 9 (As p is positive) Substitute the value of q=1 in answer options to see where qou get p2= 9. Answer is option (d)

If p and q are positive and p²q² = 18 – 3pq, then p² =

The correct option is D 9/q²
Subsitute q=1, the equation reduces to p² +18 – 3p = 0. Solving this, we get p=-6 & p=3. Hence, p²= 9 (As p is positive)

Substitute the value of q=1 in answer options to see where qou get p²= 9. Answer is option (d)