If p and q are positive integers, then the absolute difference of the coefficients of xp and xq in the expansion of (1+x)p+q is
A
0
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B
p, when p>q
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C
q, when p<q
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D
|p−q|
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Solution
The correct option is A0 Given : (1+x)p+q General term is Tr+1=p+qCr(1)p+q−rxr⇒Tr+1=p+qCrxr Coefficient of xp=p+qCp Coefficient of xq=p+qCq So, p+qCp=p+qCq Hence, the absolute difference between the coefficients is 0.