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Question

If p and q are positive integers, then the absolute difference of the coefficients of xp and xq in the expansion of (1+x)p+q is

A
0
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B
p , when p>q
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C
q , when p<q
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D
|pq|
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Solution

The correct option is A 0
Given : (1+x)p+q
General term is
Tr+1= p+qCr (1)p+qrxrTr+1= p+qCrxr
Coefficient of xp= p+qCp
Coefficient of xq= p+qCq
So, p+qCp= p+qCq
Hence, the absolute difference between the coefficients is 0.

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