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Question

If p and q are positive then the roots of the equation x2−px−q=0 are-

A
imaginary
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B
real & both positive
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C
real & both negative
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D
real & of opposite sign
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Solution

The correct option is D real & of opposite sign
Quadratic is : x2pxq=0
D=b2xac
=(p)24(1)(q)
=p2+4q>o(asp,q>o)
roots are real.
Let roots =α,β
α+β=p,αβ=q
at αβ=q<0
α and β are of opposite sign.

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