If p and q are the coeffcients of xn in (1+x)2n and (1−4x)−1/2,|x|<14 then
A
p=q
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B
p=2q
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C
q=2p
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D
p+q=2nCn
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Solution
The correct option is Ap=q The coefficient of xnin(1+x)2n is p=2nCn. The coefficient of xnin(1−4x)−1/2 is ⇒q=4n×1×3×5×...×(2n−1)2n×n! ⇒q=1×2×3×4×...×(2n)2n2×4×6×...×(2n)n! ⇒q=(2n)!n!×n!=2nCn Hence, p=q.