If p and q are the roots of the equation ax2+bx+c=0, then the value of pq+qp is
A
b2−2ac
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B
b2−2acac
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C
b2−4ac2a
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D
b2−4acac
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Solution
The correct option is Ab2−2acac and q are the roots of ax2+bx+c=0.Then p+q=−ba,pq=ca pq+qp=p2+q2pq=(p+q)2−2pqpq =(b2−a2)−2(c/a)c/a=b2−2aca2×ac=b2−2acac