If p and q are the roots of the equation $x^{2} + p x + q = 0,$ then

p = 1, q = - 2

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p = 0, q = 1

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p = - 2, q = 0

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p = - 2, q = 1

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Solution

The correct option is A $p = 1, q = - 2$
$S u m o f r o o t s = (\frac{- b}{a}) p + q = - p o r 2 p + q = 0 ⟶ E q .1 P r o d u c t o f r o o t s = (\frac{c}{a}) p q = q q (p - 1) = 0 S o e i t h e r p = 1 o r q = 0 I f p = 1, t h e n q = - 2 I f q = 0, t h e n p = 0$

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