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Question

If p and q are the roots of the quadratic equation x2(α2)xα1=0. What is the minimum possible value of p2+q2?

A
0
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B
3
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C
4
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D
5
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Solution

The correct option is D 5
x2(α2)α1=0
Then sum of roots=α2
product of roots = α1
(p+q)2=p2+q2+2pq
Thus (α2)2=p2+q2+2(α1)
p2+q2=α24α+4+2α+2=α22α+6=α22α+1+5=(α1)2+5
Thus minimum velue of p2+q2 is 5


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