If P and Q are the sum and product respectively of all integral values of x satisfying the equation |3[x]−4x|=4, then (where [.] denotes represents greatest integer function )
A
P=0
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B
P=8
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C
Q=−16
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D
Q=−9
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Solution
The correct options are AP=0 CQ=−16 ⇒|3[x]−4x|=4
⇒|3[x]−4[x]−4{x}|=4
⇒|−[x]−4{x}|=4
Put [x]=0⇒|−4{x}|=4⇒{x}=1
Put [x]=1⇒|−1−4{x}|=4⇒{x}=34
Put [x]=2⇒|−2−4{x}|=4⇒{x}=12
Put [x]=3⇒|−3−4{x}|=4⇒{x}=14
Put [x]=4⇒|−4−4{x}|=4⇒{x}=0
Put [x]=−4⇒|4−4{x}|=4⇒{x}=0
So here, we can see we get 2 integral values which is 4 and −4