If $P (¯ A) = 0.65, P (A \cup B) = 0.65,$ where A and B are two mutually exclusive events. then find P(B).

0.6

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0.3

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0.7

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none of these

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Solution

The correct option is B 0.3
$P (A \cup B) = P (A) + P (B) 0.65 = 0.35 + P (B) (∵ P (A) = 1 - P (¯ A)) \Rightarrow P (B) = 0.30$

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Similar questions

A a n d B a r e m u t u a l l y e x c l u s i v e e v e n t s o f a n e x p e r i m e n t .

I f P (¯ A) = 0.65, P (A \cup B) = 0.65 a n d P (B) = P .

F i n d t h e v a l u e o f P .

If A and B are mutually exclusive events then
(a) PA≤PB
(b) PA≥PB
(c) PA<PB
(d) None of these

P (A \cup B) = 0.85

P (A / B) = P (B / A)

P (A) = P (B)

(A \cap B) \neq ϕ

P (A / B) = \frac{P (A \cap B)}{P (B)}

P (B / A) = \frac{P (A \cap B)}{P (A)}

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