If P- 1 x-1 and Q- x 2 -1 x-1 then the value of PQ is -

The correct option is B 1 So, we need to calculate the value of PQ P= 1 x+1 and Q= x ^ 2 1 x 1 PQ= 1 x+1 × x ^ 2 1 x 1 (x ...

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Byju's Answer

Standard X

Mathematics

Multiplication of Rational Expressions

If P= 1 x+1...

Question

If $P = \frac{1}{x + 1}$ and $Q = \frac{x^{2} - 1}{x - 1}$ then the value of $P Q$ is :

x + 1

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1

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x - 1

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x^{2} - 1

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Solution

The correct option is B $1$
So, we need to calculate the value of $P Q$
$P = \frac{1}{x + 1}$ and $Q = \frac{x^{2} - 1}{x - 1}$

$P Q = \frac{1}{x + 1} \times \frac{x^{2} - 1}{x - 1}$

$(x + 1) (x - 1) = x^{2} - 1$

$P Q = \frac{x^{2} - 1}{x^{2} - 1} = 1$

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If P=1x+1 and Q=x2−1x−1 then the value of PQ is :

The correct option is B 1So, we need to calculate the value of PQP=1x+1 and Q=x2−1x−1PQ=1x+1×x2−1x−1(x+1)(x−1)=x2−1PQ=x2−1x2−1=1

If $P = \frac{1}{x + 1}$ and $Q = \frac{x^{2} - 1}{x - 1}$ then the value of $P Q$ is :

The correct option is B $1$
So, we need to calculate the value of $P Q$
$P = \frac{1}{x + 1}$ and $Q = \frac{x^{2} - 1}{x - 1}$

$P Q = \frac{1}{x + 1} \times \frac{x^{2} - 1}{x - 1}$

$(x + 1) (x - 1) = x^{2} - 1$

$P Q = \frac{x^{2} - 1}{x^{2} - 1} = 1$