If p-cos 2 -i sin 2 - q-cos 2 -i sin 2- then the value of -pq-qp-

The correct option is D 2 i sin (α+β) P=e^ 2iα, q=e^ 2iβ, √(e^ 2iαe^ 2iβ) √(e^ 2iαe^ 2iβ) e^ i(α+β) e^i(α+β) 2isin ( ...

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Theorems on Integration

If p=cos 2 ...

Question

If $p = c o s 2 α - i s i n 2 α, q = c o s 2 β + i s i n 2 β$ then the value of $\sqrt{\frac{p}{q}} - \sqrt{\frac{q}{p}} =$

2 c o s (α - β)

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2 s i n (α - β)

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2 i s i n (α - β)

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2 i s i n (α + β)

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Solution

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Similar questions

p = cos 2 α + i sin 2 α, q = cos 2 β + i sin 2 β

\sqrt{\frac{p}{q}} - \sqrt{\frac{q}{p}} =

{cos 2 α + cos 2 β + 2 cos (α + β)}

{sin 2 α + sin 2 b + 2 sin (α + β)},

a = c o s 2 α + i s i n 2 α, b = c o s 2 β, c = c o s 2 γ + i s i n 2 γ

d = c o s 2 δ + i s i n 2 δ

\sqrt{a b c d} + \frac{1}{\sqrt{a b c d}}

If $c o s α + c o s β = 0 = s i n α + s i n β$ , then prove that $c o s 2 α + c o s 2 β = - 2 c o s (α + β)$

If a root of the equations $x^{2} + p x + q = 0$ and $x^{2} + α x + β = 0$ is common, then its value will be ( where p ≠ α and q ≠ β )

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