Question

If p=$3+\frac{1}{p}$ then the value of $\frac{p}{p^2+p-1}$ is

• A. 7/4
• B. 5/4
• C. 3/4
• D. 1/4

Answer 1

The correct option is D 1/4

Given $p=3+\frac{1}{p}\Rightarrow p-\frac{1}{p}=3$

Then $\frac{p}{p^2+p-1}$

This written as

$\frac{p^2+p-1}{p}=p+1-\frac{1}{p}=p+\frac{1}{p}+1=3+1=4$

So $\frac{p}{p^2+p-1}=\frac{1}{4}$