If P-x2-36-x2-49 and Q -x-6-x-7- then find the value of P -Q-

P = x^2 36x^2 49 = #10;(x+6)(x 6)(x+7)(x 7) Q=x+6x+7 Then , PQ #10;= (x+6)(x 6)(x+7)(x 7)x+6x+7 PQ = (x+6)(x 6)(x+7)(x 7)× #160; x+7x ...

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Definition of Functions

If P=x2-36/...

Question

If $P = \frac{x^{2} - 36}{x^{2} - 49}$ and Q $= \frac{x + 6}{x + 7}$ , then find the value of P $/$ Q.

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P = \frac{x^{2} - 36}{x^{2} - 49}

Q = \frac{x + 6}{x + 7}

\frac{P}{Q}

P = {x / x^{2} + 14 x + 40 = 0}

Q = {x / x^{2} - 5 x + 6 = 0}

R = {x / x^{2} + 17 x - 60 = 0}

X = {- 20, - 10, - 4, 2, 3, 4}

P \cup Q

\frac{x^{2} - 36}{x^{2} - 49} \div \frac{x + 6}{x + 7}

If $(x + a)$ is a factor of $x^{2} + p x + q$ and $x^{2} + m x + n$ , then the value of $a$ is

P = \frac{1}{x + 1}

Q = \frac{x^{2} - 1}{x - 1}

P Q

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