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Byju's Answer
Standard IX
Physics
Vernier Caliper
If PE=0.42,...
Question
If
P
(
E
)
=
0.42
, then what is the value of
P
(
n
o
t
E
)
?
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Solution
P(E)+P(not E) = 1.
0.25+ P(not E)=1
P(not E) = 1-0.25
P(not E) = 0.75
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