Question

If P = {factors of 36} and Q = {factors of 48}, find P $\cup$ Q $=K$, and if sum of each element in $K$ is $s$, then $\frac{s+3}{10}-10$ $=$

Answer 1

Factors of $36$ are $1,2,3,4,6,9,12,18,36$
Factors of $48$ are $1,2,3,4,6,8,12,16,24,48$
So, $P$ $=$ { $1,2,3,4,6,9,12,18,36$ }
and $Q$ $=$ { $1,2,3,4,6,8,12,16,24,48$ }
Union of two sets has all the elements of both the sets.
So, $P\cup Q=$ { $1,2,3,4,6,8,9,12,16,18,24,36,48$ }

$s=187=\frac{s+3}{19}-10=\frac{187+3}{19}-10=9$