If p-0- q-0 then roots of x2-p x-q-0 areA- ImaginaryB- Real and of opposite signC- Real and positiveD- Real and negative

The correct option is B Real and of opposite sign D = p^2 + 4q 0 and ∝ β = q 0 ∴ roots are real and of opposite sign. ...

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Standard XII

Mathematics

Higher Order Equations

If p>0, q>0 t...

Question

If $p > 0, q > 0$ then roots of $x^{2}$ - px - q = 0 are :

Imaginary

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Real and of opposite sign

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Real and positive

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Real and negative

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Solution

The correct option is B
Real and of opposite sign

$D = p^{2} + 4 q > 0 a n d \propto β = - q < 0$

$∴$ roots are real and of opposite sign.

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If p> 0,q > 0 then roots of x2 - px - q = 0 are :

The correct option is B Real and of opposite sign D=p2+4q > 0and ∝ β=−q < 0 ∴ roots are real and of opposite sign.

If $p > 0, q > 0$ then roots of $x^{2}$ - px - q = 0 are :

The correct option is B
Real and of opposite sign

$D = p^{2} + 4 q > 0 a n d \propto β = - q < 0$

$∴$ roots are real and of opposite sign.