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Standard X
Mathematics
Impossible Event
If p has n+1 ...
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If p has n+1 and q has n fair coins then probability that p has more heads than q
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Q.
Suppose A has (n+1) and B has n fair coins which they flip. Let
p
k
denote the probability that A obtains exactly
k
(
0
≤
k
≤
n
+
1
)
heads more than B. Value of
Q.
A coin has probability
p
of showing head when tossed. It is tossed
n
times. Let
p
n
denote the probability that no two (or more) consecutive heads occur, then
Q.
A bag contains n+1 coins. It is known that one of these coins has heads on both sides, whereas the other coins are fair. One coin is selected at random and tossed. If the probability that the toss results in heads is 7/12, find n
Q.
N coins, each with probability
p
of getting head are tossed together. In the options q = 1-p, The probability of getting odd number of heads is
Q.
Two persons
A
and
B
have respectively
n
+
1
and
n
coins, which they toss simultaneously. Then probability
P
that
A
will have more heads than
B
is:
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