If P is a point in the interior of ∆ABC then fill in the blanks with > or < or =.

(i) PA + PB ...... AB
(ii) PB + PC ...... BC
(iii) AC ...... PA + PC

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Solution

(i) $>$
(ii) $>$
(iii) $<$

The reason for the above three is that the sum of any two sides of a triangle is greater than the third side.

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If P is a point in the interior of ∆ABC then fill in the blanks with > or < or =. (i) PA + PB ...... AB (ii) PB + PC ...... BC (iii) AC ...... PA + PC

(i) > (ii) > (iii) < The reason for the above three is that the sum of any two sides of a triangle is greater than the third side.

If P is a point in the interior of ∆ABC then fill in the blanks with > or < or =.

(i) PA + PB ...... AB
(ii) PB + PC ...... BC
(iii) AC ...... PA + PC

(i) $>$
(ii) $>$
(iii) $<$

The reason for the above three is that the sum of any two sides of a triangle is greater than the third side.