If P is a point on the hyperbola $16 x^{2} - 9 y^{2} = 144$ whose foci are $S_{1} a n d S_{2}, t h e n P S_{1} \sim P S_{2} =$

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Solution

The correct option is B
6

$\frac{x^{2}}{3^{2}} - \frac{y^{2}}{4^{2}} = 1$ . Therefore $P S_{1} \sim P S_{2} = 2 (3) = 6$ .

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Similar questions

If P is a point on the hyperbola $16 x^{2} - 9 y^{2} = 144$ whose foci are $S_{1} a n d S_{2}, t h e n P S_{1} \sim P S_{2} =$

A

B

P

P

| P A - P B | = k

k

S_{1}

S_{2}

| P S_{1} - P S_{2} | < S_{1} S_{2}

e x^{2} + π y^{2} - 2 e^{2} x - 2 π^{2} y + e^{3} + π^{3} = π e

P

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