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Question

If p is a prime number, show that the coefficients of the terms of (1+x)p1 are alternately greater and less by unity than some multiple of p.

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Solution

Let the co efficients be denoted by C0,C1,C2,.........Cr,,..
then Cr=(p1)(p2)(p3)...(pr)r!
=M(p)+(1)r!r!=M(p)r!+(1)r
Now, Cr is a positive integer;hence
M(p)r!+(1)r must be a positive integer, and since p is a prime number it must be a multiple of p; therefore
Cr=M(p)+(1)r

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