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Question

If P is a prime number then npn is divisible by p when n is a

A
natural number greater than 1
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B
odd number
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C
even number
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D
None of these
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Solution

The correct option is D natural number greater than 1
Let P(n): npn

when p=2

P(n)= n2n

P(1)=0 which is divisible all nN

P(2)=2 which is divisible by 2

P(3)=6 which is divisible by 2

Hence P(n) is divisible by 2 when n is greater than 1

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