Question

If $P$ is an integer between $0$ and $9,R-P=16229$ and $R$ divisible by $11$, then find the value of $\frac{P+R-1}{3}$

• A. $5014$
• B. $4514$
• C. $5414$
• D. $5114$

Answer 1

The correct option is C $5414$

$R-P=16229$

P be b/w $0\&9$

and R is divisible by 11

So, $R=\frac{16229+P}{11}$

(and Reminder = 0)

So, $\Rightarrow \left(\frac{11+P}{11}\right)$ so $P=7$

and $R=16229+7$

$=16236$

So $\frac{P+R+1}{3}$

$\Rightarrow \frac{16236+7-1}{3}$

$\Rightarrow \frac{16242}{3}=5414$

Option C is correct